1.

In a certain field, the potential energy is U = ax^2 - bx^3, where a and b constants. The particle is in stable equilibrium at x equal to(1) Zero(2) a/3b(3) 2a/3b(4) 2a/b

Answer»

ANSWER:

U=ax2-bx3

Explanation:

du/dx=2ax-3bx2

d2u/dx2=2a-3bx

2a-3bx=0

2a=3bx

x=2a/3b



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