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In a certain field, the potential energy is U = ax^2 - bx^3, where a and b constants. The particle is in stable equilibrium at x equal to(1) Zero(2) a/3b(3) 2a/3b(4) 2a/b |
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Answer» U=ax2-bx3 Explanation: du/dx=2ax-3bx2 d2u/dx2=2a-3bx 2a-3bx=0 2a=3bx x=2a/3b |
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