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In a bus, the cost of 2 tickets for stoppage A and 3 tickets for stoppage B is Rs 46, whereas the cost of 3 tickets for stoppage A and 5 tickets for stoppage B is Rs 74. Find the fare from stoppage A to B. |
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Answer» Let Fare of A = Rs x and fare of B = Rs y, then 2x + 3y = 46 3x + 5y = 74 Multiply by 3 in eq. (i) and by 2 in eq. (ii) and then subtracted (ii) from (i). 6x + 9y – 6x – 10y = 138 – 148 ⇒ -y = -10 ⇒ y = 10 putting y = 10 in equ. (i) 2x + 3 × 10 = 46 x = \(\frac { 46-30 }{ 2 }\) = 8 x = 8 Hence, fare of A Rs 8, fare of B = Rs 10. |
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