In a ∆ABC, angle A is obtuse, PB is perpendicular to AC and QC is pe – InterviewSolution

1.	In a ∆ABC, angle A is obtuse, PB is perpendicular to AC and QC is perpendicular to AB and AB x AQ= AC x AP.Prove that BC x BC= (AC x CP + AB x BQ)
Answer» In a ∆ABC, angle A is obtuse, PB is perpendicular to AC and QC is perpendicular to AB and AB x AQ= AC x AP. Prove that BC x BC= (AC x CP + AB x BQ)

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