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In a AABC, ZA+ ZB = 65 and 2B + 2C = 140 . Find the angles. |
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Answer» Given<A+<B=65°<B+<C=140°We know that <A+<B+<C=180°(angle sum property) (<A+<B)+<C=18065+<C=180<C=180-65=115° <B+<C=140°=<B+115=140=<B=140-115=25° <A+<B=65°=<A+25=65=<A=65-25=40° Thus <A=40°<B=25°<C=115° |
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