1.

In a AABC, ZA+ ZB = 65 and 2B + 2C = 140 . Find the angles.

Answer»

Given<A+<B=65°<B+<C=140°We know that <A+<B+<C=180°(angle sum property)

(<A+<B)+<C=18065+<C=180<C=180-65=115°

<B+<C=140°=<B+115=140=<B=140-115=25°

<A+<B=65°=<A+25=65=<A=65-25=40°

Thus <A=40°<B=25°<C=115°



Discussion

No Comment Found