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In a 2 stage process Q1 = 5 J, Q2 = 10 J, if the change in internal energy in first stage is 10 J and the total change in internal energy is 20 J, what is the work do done in second stage?(a) 0(b) 5 J(c) 10 J(d) – 5 J |
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Answer» Right choice is (a) 0 To explain I would say: Change in internal energy in second stage = 20 – 10 =10 J, Work done in second stage = 10 – 10 = 0. |
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