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--ILULULLWW.et axes applied to a train moving at 90 km/hEuce a retardation of 5 m/s? What distanceFit cover before coming to a stop ? |
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Answer» Answer: 0.5 m Explanation: the SPEED of TRAIN is 90km/hr = 25m/s retardation = 5m/s² using the equation v² - u2 = 2AS 5² - 0² = 2 ×25 s 25 = 50s S = 1/2 ANS |
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