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--ILULULLWW.et axes applied to a train moving at 90 km/hEuce a retardation of 5 m/s? What distanceFit cover before coming to a stop ?​

Answer»

Answer:

0.5 m

Explanation:

the SPEED of TRAIN is 90km/hr = 25m/s

retardation = 5m/s²

using the equation v² - u2 = 2AS

5² - 0² = 2 ×25 s

25 = 50s

S = 1/2 ANS



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