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iJ—_—(lc—osfi)(l— ८०89)(1+cos 0) (1-cosB) |
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Answer» √( 1-cos theeta)^2/√1-cos^2 theeta= √((1-cos theeta/sin theeta)^2= 1-cos theeta/ sin theta cosectheta - cot thetathanksplease like the solution 👍 ✔️👍 |
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