(iii) tan 15° + cot 15° = 4

1.	(iii) tan 15° + cot 15° = 4
Answer» GIVEN Tan 15 + cot 15 = sin 15/cos 15 + cos 15/sin 15 = (sin^2 15 + cos^2 15)/sin 15 cos 15 = 1/1/2 sin (15 + 15) - sin(15 - 15) = 1/(1/2 sin 30) = 2/sin 30 = 2/ (1/2) = 4. LHS = RHS.

Answer»

GIVEN Tan 15 + cot 15

= sin 15/cos 15 + cos 15/sin 15

= (sin^2 15 + cos^2 15)/sin 15 cos 15

= 1/1/2 sin (15 + 15) - sin(15 - 15)

= 1/(1/2 sin 30)

= 2/sin 30

= 2/ (1/2)

= 4.

LHS = RHS.

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(iii) tan 15° + cot 15° = 4​

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(iii) tan 15° + cot 15° = 4