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(ii) The modulus of 1 +8i is8+8+(1+ ৪ -এর মডিউলাস হবে) |
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Answer» Let z = (8+i)/(1 + 8i) = (8+i)*(1 -8i)/ (1 + 8i)(1 - 8i) = (8 - 64i + i + 8)/ (1 + 64) = (16 - 63i)/65 Modulus of z= sqrt[(16/65)^2 + (-63/65)^2]= sqrt[(256 + 3969)/4225]= sqrt(4225/4225)= sqrt(1) = 1 |
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