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(ii) Find the number of terms in the following series.4,7,10,...,148 |
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Answer» Given series 4, 7, 10,...... 148 is an AP First term a = 4, common difference d = 7 - 4 = 3 nth term of AP is given byan = a + (n - 1)d Let number of terms in series be mso,148 = 4 + (m-1)3148 = 4 + 3m - 33m = 148 - 13m = 147m = 147/3 = 49 Therefore,Number of terms in given series is 49 Given -AP = 4,7,10,......,148First term ( a ) = 4 common difference (d) = 7-4=3n term of AP is indicated by an = a+(n-1)d an = 148 ( given )148 = 4+(n-1)3148 = 4+3n-3147 = 3n147/3 = n49 = nSo, no. of terms are 49. |
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