(ii) cost of the canvas required to make the lellt,What length of tarp

1.	(ii) cost of the canvas required to make the lellt,What length of tarpaulin 3 m wide will be required to make conical tent of height 8 mand base radius 6 m? Assume that the extra length of material that will be required forstitching margins and wastage in cutting is approximately 20 cm (Use π = 314).
Answer» Given a conical tent with Height ( h ) = 8m Radius ( r ) = 6m So, its length = l2= h2+ r2 = l2= ( 8 )2m + ( 6 )m2 = l2= 64m + 36m = l2= 100m = l = 10m Curved surface area of the cone = TTrl = 3.14 x 6m x 10m = 188.4 cm2 The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m So, its length = l - 0.2m and its width = 3m area of sheet = CSA of tent so the area of the trapaulln = l x b = ( l - 0.2m ) x 3m = 188.4m2 = l - 0.2m = 62.8m2 = l = 63m Therefore, length of the trapaulin sheet required is 63m. Hit like if you find it useful!

(ii) cost of the canvas required to make the lellt,What length of tarpaulin 3 m wide will be required to make conical tent of height 8 mand base radius 6 m? Assume that the extra length of material that will be required forstitching margins and wastage in cutting is approximately 20 cm (Use π = 314).

Answer»

Given a conical tent with

Height ( h ) = 8m

Radius ( r ) = 6m

So, its length = l2= h2+ r2

= l2= ( 8 )2m + ( 6 )m2

= l2= 64m + 36m

= l2= 100m

= l = 10m

Curved surface area of the cone = TTrl

= 3.14 x 6m x 10m

= 188.4 cm2

The extra length of material that will be required for stiching margins and wastages in cutting is approx 20 cm = 0.2m

So, its length = l - 0.2m

and its width = 3m

area of sheet = CSA of tent

so the area of the trapaulln = l x b

= ( l - 0.2m ) x 3m = 188.4m2

= l - 0.2m = 62.8m2

= l = 63m

Therefore, length of the trapaulin sheet required is 63m.

Hit like if you find it useful!