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Iff(x)={1−|x|,|x|≤1|x|−1,|x|>1, and g(x)=f(x−1)+f(x+1). The value of 5∫−3g(x)dx

Answer» Iff(x)={1|x|,|x|1|x|1,|x|>1, and g(x)=f(x1)+f(x+1). The value of 53g(x)dx


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