Ifa- 6+5 and b-then what will be the value of a + b

1.	Ifa- 6+5 and b-then what will be the value of a + b
Answer» a = √6+5 b = 1/a = 1(√6-5)/(√6+5)(√6-5) = √6-5 so, a²+b² = (√6+5)² + (√6-5)² = (√6)²+(5)²+10√6 +(√6)²+(5)²-10√6 = 6+25+6+25 = 62 a = √6+5 b = 1/a = 1(√6-5)/(√6+5)(√6-5) = √6-5 so, a²+b² = (√6+5)² + (√6-5)² = (√6)²+(5)²+10√6 +(√6)²+(5)²-10√6 = 6+25+6+25 = 62 can you explain 1/a

Answer»

a = √6+5

b = 1/a = 1*(√6-5)/(√6+5)*(√6-5) = √6-5

so, a²+b² = (√6+5)² + (√6-5)² = (√6)²+(5)²+10√6 +(√6)²+(5)²-10√6 = 6+25+6+25 = 62

a = √6+5

b = 1/a = 1*(√6-5)/(√6+5)*(√6-5) = √6-5

so, a²+b² = (√6+5)² + (√6-5)² = (√6)²+(5)²+10√6 +(√6)²+(5)²-10√6 = 6+25+6+25 = 62

can you explain 1/a

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