1.

If zeros of the puadratic polynomial x2+(a+1)x+b are 2 and -3 find the value of a and b​

Answer»

Answer:

\large\boxed{\sf{a=0,\;\;b=-6}}

Step-by-step explanation:

Given a quadratic POLYNOMIAL such that,

{x}^{2}+(a+1)x+b

Also, the roots of the polynomial are 2 and -3.

Now, we know that, General form of a quadratic polynomial is ,

A{x}^{2}+Bx+C

On Comparing the coefficients, we have,

  • A = 1
  • B = a + 1
  • C = b

Now, we know that,

SUM of roots = -B/A

=> -(a+1)/1 = 2 +(-3)

=> -(a+1) = 2 -3

=> a + 1 = -(-1)

=> a = 1-1

=> a = 0

And, also, we know that,

Product of roots = C/A

=> b/1 = 2(-3)

=> b = -6

Hence, the VALUES of a = 0 and b = -6.


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