1.

If z =t^5 - 3t^4 +2 t^3 +8 then find the dz/dt and find value of the derivative at t=1

Answer»

ANSWER:

\frac{dz}{dt} = \frac{d(}{dt} {t}^{5} - 3 {t}^{4} + 2 {t}^{3} + 8)

= 5 {t}^{4} - 12 {t}^{3} + 6 {t}^{2} + 0

At t=1

= 5 \times 1 - 12 \times 1 + 6 \times 1

= 5 - 12 + 6

= 11 - 12

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