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If `z=re^i theta` then `|e^(iz)|` is equal to: |
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Answer» `z=re^(itheta),iz=ire^(itheta)` `=l8r{costheta+isintheta}` `=r(sintheta+icostheta)` `e^(iz)=e^r*(icostheta-sintheta)` `=e^(-rsintheta)*e^(ircostheta)` `|e^(iz) | =|e^(-rsintheta*e*^(ircostheta)` `=e^(-rsontheta)*|costheta|isintheta|^(rcostheta)` `=e^(-rsintheta)*(1)^rcostheta` `=e^(-rsintheta)`. |
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