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| 1. |
If `|z + 2i| |
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Answer» `|z+2i|<=1` `z+2i<=e^i` `z<=-2i+e^(itheta)` `|iz+zi-4|=|iz+6-3i-4|` `=|iz+2-3i|` `=|2+e^(i(theta+pi/2) +2-3i|` `=|4-3i+e^(1(theta+pi/2)|` =6 option 2 is correct |
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