1.

If `|z + 2i|

Answer» `|z+2i|<=1`
`z+2i<=e^i`
`z<=-2i+e^(itheta)`
`|iz+zi-4|=|iz+6-3i-4|`
`=|iz+2-3i|`
`=|2+e^(i(theta+pi/2) +2-3i|`
`=|4-3i+e^(1(theta+pi/2)|`
=6
option 2 is correct


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