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If z=-1+i then arg(z)=?

Answer»

ANSWER:

{\large{\overbrace{\underbrace{\purple{your \: answer:arg(z) = \sqrt{2} }}}}} \\ \\ \red♡ dear *----*

Step-by-step EXPLANATION:

{\boxed{\bf\ z = x + iy }}\\ \\ \bf\ \: modulas \: of \: z = |z| \\ \\ \bf\underline{\implies |z| = \sqrt{ {x}^{2} + {y}^{2} } } \\ \\ \\ \bf\underline{here} \: \: \bigstar z = - 1 + i \: \: \bigstar\\ \\ \bf\ x = - 1 \: and \: y = 1 \\ \\ \bf\ modulas \: of \: z = |z| \\ \\ \bf\ : \implies \sqrt{ {x}^{2} + {y}^{2} } \\ \\ \bf\ : \implies \sqrt{ {1}^{2} + {1}^{2} } \\ \\ \bf\ : \implies \sqrt{1 + 1} \\ \\ \boxed{\implies \sqrt{2} }\\ \\ \bf\red{ \mapsto \: arg(z) = \sqrt{2} }

\large\boxed{ \fcolorbox{lime}{yellow}{hope \: it \: help \: you}}


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