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If y=(x+√x2−1)15+(x−√x2−1)15, then (x2−1)d2ydx2+xdydx is equal to: |
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Answer» If y=(x+√x2−1)15+(x−√x2−1)15, then (x2−1)d2ydx2+xdydx is equal to: |
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