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If `y=x^2+2x-3`,`y-x` graph isA. B. C. D. |
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Answer» Correct Answer - C `y=x^2+2x-3`, If we compare with `y=ax^2+bx+c` The coefficient of `x^2` is positive hence parabola opens up At `x=0`,`y=-3` At `y=0`,`x=(-2+-sqrt(4+12))/(2xx1)` `=(-2+-4)/(2)=-1+-2=-3`,1. Hence, option ( c) is correct. |
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