1.

If y=[x]2+2{x}[x]+100∑r=1{x+r}2100, then ∫y⋅dx=(where [.] and {.} are greatest integer function and fractional part function respectively and c is integration constant)

Answer»

If y=[x]2+2{x}[x]+100r=1{x+r}2100, then ydx=

(where [.] and {.} are greatest integer function and fractional part function respectively and c is integration constant)



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