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if y=sin(log x) then x^(2)y_(2) + xy_(1) + y=0 then |
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Answer» y = sin(logx) y1 = \(\frac{cos(logx)}{x}\) xy1 = cos(log x). Again differentiate w.r.t. x xy2 + y11 = \(\frac{-sin(logx)}{x}\) x2y2 + xy1 = -y ⇒ x2y2 + xy1 + y = 0. |
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