If y=mx bisects the angle between the lines y=x2(sin2θ+tan2θ)+2xycos – InterviewSolution

1.	If y=mx bisects the angle between the lines y=x2(sin2θ+tan2θ)+2xycosθ+y2sec2θ=0 when θ=π3. If the value of m is a±√b4, then b−10a=?
Answer» If $y = m x$ bisects the angle between the lines $y = x^{2} ({sin}^{2} θ + {tan}^{2} θ) + 2 x y cos θ + y^{2} {sec}^{2} θ = 0$ when $θ = \frac{π}{3} .$ If the value of $m$ is $\frac{a \pm \sqrt{b}}{4},$ then $b - 10 a = ?$

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