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If y = log10x then dy/dx = ?A. 1/xB. 1/x (log 10)C. 1/x(log 10)D. none of these

Answer»

Answer is: C. 1/x(log 10)

Given that y = log10 x

Using the property that loga b = logeb/logea, we get

y = logex/loge10

Differentiating with respect to x, we get

dy/dx = 1/xloge10



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