Saved Bookmarks
| 1. |
If y = log10x then dy/dx = ?A. 1/xB. 1/x (log 10)C. 1/x(log 10)D. none of these |
|
Answer» Answer is: C. 1/x(log 10) Given that y = log10 x Using the property that loga b = logeb/logea, we get y = logex/loge10 Differentiating with respect to x, we get dy/dx = 1/xloge10 |
|