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`"if y"="cos"^(-1)((5"cos" x-12 "sin"x)/(13)),` where `x in (0,(pi)/(2)) , " then "(dy)/(dx) " is"-`A. 1B. -1C. 0D. None of these |
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Answer» Correct Answer - A `y = " cos"^(-1) [(5)/(13) " cos " x - (12)/(13) " sin "x]` `y = " cos"^(-1) underset("cos"alpha)underset(darr)([(5)/(13))) " cos " x - underset("sin"alpha)underset(darr)((12)/(13)) " sin "x"]"` `="cos"^(-1) ["cos"(x+alpha)]` `y= x+alpha " "y^(1) =1` |
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