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If (y-3) is a factor of y³-2y²-9y+18 then find the other two factors |
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Answer» ER: Step-by-step explanation: t is GIVEN that (y-3) is a factor of the three-degree polynomial equation y³-2y²-9y+18 =0 Now, we will factorize the above expression USING a factor as (y-3). HENCE, y³-2y²-9y+18 =0 ⇒ y³-3y²+y²-3y-6y+18 =0 ⇒y²(y-3)+y(y-3)-6(y-3) =0 ⇒(y-3)(y²+y-6)= 0 ⇒(y-3)(y²+3y-2y-6) =0 ⇒(y-3)(y+3)(y-2)=0 Hence, from the above expression, it is clear that the other two factor of equatio (1) are (y+3) and (y-2). (Answer) |
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