If (y + 1/y) = 8 then, (y² +1/y²) is

1.	If (y + 1/y) = 8 then, (y² +1/y²) is
Answer» $\huge\red {\bf {\underline {Solution:-}}}$ ${\tt {y + \frac{1}{y} = 8}}$ $⇒{\tt { {(y + \frac{1}{y}) }^{2} = {8}^{2}}}$ $⇒{\tt { {y}^{2} + 2 \times y \times \frac{1}{y} + \frac{1}{ {y}^{2} } = 64}}$ $⇒ {\tt {{y}^{2} + 2 + \frac{1}{ {y}^{2} } = 64}}$ $⇒{\tt { {y}^{2} + \frac{1}{ {y}^{2} } = 64 - 2}}$ $⇒{\tt { {y}^{2} + \frac{1}{ {y}^{2} } = 62}}$ _______________________ *HOPE* It *HELPS* UH! ❤

Answer»

$\huge\red {\bf {\underline {Solution:-}}}$