1.

If xy+yx=−1, where x,y≠0 then the value of (x3−y3) is (a) 1 (b)−1 (c) 0(d) 12

Answer»

If xy+yx=−1, where x,y≠0 then the value of (x3−y3) is
(a) 1

(b)−1

(c) 0

(d) 12



Discussion

No Comment Found