If x3 - 1 can be written as (x−α0) (x−α1) (x−α2).Where,α0,α

1.	If x3 - 1 can be written as (x−α0) (x−α1) (x−α2).Where,α0,α1 and α2 are the roots of the equation and 1(3−α0) + 1(3−α1) + 1(3−α2) = k26. Find the value of k. __
Answer» If $x^{3}$ - 1 can be written as $(x - α_{0})$ $(x - α_{1})$ $(x - α_{2})$ .Where, $α_{0}$ , $α_{1}$ and $α_{2}$ are the roots of the equation and $\frac{1}{(3 - α_{0})}$ + $\frac{1}{(3 - α_{1})}$ + $\frac{1}{(3 - α_{2})}$ = $\frac{k}{26}$ . Find the value of k. __

If x3 - 1 can be written as (x−α0) (x−α1) (x−α2).Where,α0,α1 and α2 are the roots of the equation and 1(3−α0) + 1(3−α1) + 1(3−α2) = k26. Find the value of k. __

Answer»

If $x^{3}$ - 1 can be written as $(x - α_{0})$ $(x - α_{1})$ $(x - α_{2})$ .Where, $α_{0}$ , $α_{1}$ and $α_{2}$ are the roots of the equation

and $\frac{1}{(3 - α_{0})}$ + $\frac{1}{(3 - α_{1})}$ + $\frac{1}{(3 - α_{2})}$ = $\frac{k}{26}$ . Find the value of k.