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If x2+y2 =49and x-y=3 then find the value of x3-y3 |
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Answer» ANSWER: ______________________ GIVEN that, x2+y2=49 x-y=3 We Know That, (x-y)^2=x2-2xy+y2 =>3^2 =49-2xy =>9=49-2xy =>49-2xy=9 =>-2xy=9-49 =>-2xy= - 40 =>xy = -40 ÷ (-2) =>xy = 20 By Putting the Value of x3-y3, We get x3-y3 =(x-y)(x2+y2+xy) =3(49+xy) =3×49+20 =3×69 = 207 (ANS) __________________________ Hope this is CORRECT and Useful for you. Thanks. |
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