1.

If (x2+x+1)+(x2+2x+3)+(x2+3x+5)+⋯+(x2+20x+39)=4500 for x>0, then the value of x is

Answer»

If (x2+x+1)+(x2+2x+3)+(x2+3x+5)++(x2+20x+39)=4500 for x>0, then the value of x is



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