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If x2 +-= 6, find the value of x4(b). |
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Answer» x²+1/x²=6sq both sides,(x²+1/x²)² = (6)²(x²)²+2×(x²)×(1/x²)+(1/x²)²=36then we cut x² and 1/x²x⁴+1/x⁴=36-2x⁴+1/x⁴=34 |
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