If x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and

1.	If x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and b.
Answer» Answer: 11, -6 Step-by-step EXPLANATION: x²-3x+2 has two roots 1,2 as x²-3x+2 DIVIDES x³-6x²+ax+b ,1 and 2 are ALSO roots of x³-6x²+ax+b SUBSTITUTE 1 in x³-6x²+ax+b ==> 1-6+a+b=0 ==>a+b=5 (1) substitute 2 in x³-6x²+ax+b ====>8-24+2a+b=0 ===>2a+b=16 (2) solving 1,2 a=11,b=-6

If x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and b.

Answer»

Answer:

11, -6

Step-by-step EXPLANATION:

x²-3x+2 has two roots 1,2

as x²-3x+2 DIVIDES x³-6x²+ax+b ,1 and 2 are ALSO roots of x³-6x²+ax+b

SUBSTITUTE 1 in x³-6x²+ax+b

==> 1-6+a+b=0

==>a+b=5 (1)

substitute 2 in x³-6x²+ax+b

====>8-24+2a+b=0

===>2a+b=16 (2)

solving 1,2

a=11,b=-6

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If x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and b.​

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If x²-3x+2 divides x³-6x²+ax+b exactly,then find the value of a and b.