If |x2 – 12x + 32| + |x2 – 9x + 20| = 0. Then find the value of

1.	If \|x2 – 12x + 32\| + \|x2 – 9x + 20\| = 0. Then find the value of x.1. x = 52. x = 43. x = 84. x = 3
Answer» Correct Answer - Option 2 : x = 4 CONCEPT: The modulus of a given function gives the magnitude of that function. Modulus Function is defined as the real valued function. The real function f: R → R defined by f (x) = \|x\|= x, x > 0, and f (x) = \|x\|= -x, if x < 0. ∀ x ∈ R is called the modulus function. CALCULATIONS: Given \|x² – 12x + 32\| + \|x² – 9x + 20\| = 0. Every modulus function is a non-negative function and if two non-negative functions add up to get zero then individual function itself equal to zero simultaneously. x² – 12x + 32 for x = 4 or 8 x² – 9x + 20 for x = 4 or 5 Both the equations are zero at x = 4 So, x = 4 is the only solution for this equation.

If |x2 – 12x + 32| + |x2 – 9x + 20| = 0. Then find the value of x.1. x = 52. x = 43. x = 84. x = 3

Answer» Correct Answer - Option 2 : x = 4

CONCEPT:

The modulus of a given function gives the magnitude of that function. Modulus Function is defined as the real valued function.

The real function f: R → R defined by f (x) = |x|= x, x > 0, and f (x) = |x|= -x, if x < 0. ∀ x ∈ R is called the modulus function.

CALCULATIONS:

Given |x² – 12x + 32| + |x² – 9x + 20| = 0.

Every modulus function is a non-negative function and if two non-negative functions add up to get zero then individual function itself equal to zero simultaneously.

x² – 12x + 32 for x = 4 or 8

x² – 9x + 20 for x = 4 or 5

Both the equations are zero at x = 4

So, x = 4 is the only solution for this equation.

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