1.

If x² + 1/x² = 38, find the value of: x4 + 1/x4.​

Answer»

GIVEN :

\\ \implies \bf {x}^{2} +  \dfrac{1}{ {x}^{2} } = 38 \\

TO FIND :

\\ \implies \bf {x}^{4} +  \dfrac{1}{ {x}^{4} } =?\\

SOLUTION :

\\ \implies \bf {x}^{2} +  \dfrac{1}{ {x}^{2} } = 38 \\

SQUARE on both sides –

\\ \implies \bf  \bigg({x}^{2} +  \dfrac{1}{ {x}^{2} } \bigg)^{2}  =(38)^{2}  \\

\\ \implies \bf  \bigg({x}^{2} +  \dfrac{1}{ {x}^{2} } \bigg)^{2}  =1444 \\

USING IDENTITY

\\ \implies \large\pink{ \boxed{\bf  (a + b)^{2}  = {a}^{2}   +  {b}^{2} + 2ab}}\\

• So that –

\\ \implies \bf   {({x}^{2})}^{2} +  \bigg(\dfrac{1}{ {x}^{2} } \bigg)^{2}   + 2( {x}^{2})\bigg(\dfrac{1}{ {x}^{2} } \bigg)=1444 \\

\\ \implies \bf  {x}^{4} +\dfrac{1}{ {x}^{4} }+ 2 \cancel{( {x}^{2})}\bigg(\dfrac{1}{ \cancel{ {x}^{2} }} \bigg)=1444 \\

\\ \implies \bf  {x}^{4} +\dfrac{1}{ {x}^{4} }+ 2=1444 \\

\\ \implies \bf  {x}^{4} +\dfrac{1}{ {x}^{4} }=1444 - 2 \\

\\ \implies \large \red { \boxed{\bf  {x}^{4} +\dfrac{1}{ {x}^{4} }=1442 }}\\



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