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If ∫x19dxx5(x5−√x10−x−10)=x30m+(x20−1)3/2n+C, where C is arbitrary constant of integration and m,n∈N, then the value of (m+n) is

Answer» If x19dxx5(x5x10x10)=x30m+(x201)3/2n+C, where C is arbitrary constant of integration and m,nN, then the value of (m+n) is


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