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If x1 and x2 satisfythe equation 2^2x-8.2^x+12=0 then find x1+x2 |
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Answer» <P>Answer: Assume that, 2^x = p Then, p^2 - 8p + 12 = 0 p^2 - 2p - 6p + 12 = 0 p ( p - 2 ) - 6 ( p - 2 ) = 0 ( p - 6 ) ( p - 2 ) = 0 p = 6 , 2 now, 2^x1 = 6 and 2^X2 = 2 2^x1 + 2^x2 = 6 + 2 x1 + x2 = 8 Hope that the answer is helpful to you Follow me |
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