1.

If x, y, z are positive integers and 3x=4y=5z. What is the laest value of x+y+z?

Answer»

Step-by-step explanation:

3x=4y=5z=K then X=k/3,y=k/4,z=k/5and k/3+k/4+k/5 =k(20+15+12)/60=47/60)k



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