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If x+y-z=4, 3x+ 3y+ z=12,(x+3y)^2 -z^{2 }=36, then find the value ofx. |
| Answer» If x+y-z=4, 3x+ 3y+ z=12,(x+3y)^2 -z^{2 }=36, then find the value ofx. | |