1.

If x+y+z=12and x2+y2+,z2=64then xy +yz+zx​

Answer»

ANSWER:

Step-by-step explanation:

Squaring both SIDES

(x+y+z)

2

=x

2

+y

2

+z

2

+2(xy+yz+zx)

we can substitute GIVEN values

(x+y+z)

2

=18+(2×9)

(x+y+z)

2

=36

(x+y+z)=6



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