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If x+y+z=12and x2+y2+,z2=64then xy +yz+zx |
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Answer» Step-by-step explanation: Squaring both SIDES (x+y+z) =x 2 +y 2 +z 2 +2(xy+yz+zx) we can substitute GIVEN values (x+y+z) 2 =18+(2×9) (x+y+z) 2 =36 (x+y+z)=6 |
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