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If ×+y+z=0show that ×3+y3+z3=3xyz |
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Answer» Step-by-step EXPLANATION: x3+y3+z3-3xyz=(x+y+z)(x2+y2+z2-xy-yz-zx) x3+y3+z3-3xyz=0×(x2+y2+z2-xy-yz-zx) x3+y3+z3-3xyz=0 x3+y3+Z3=3xyz |
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