1.

If x+y+z =0, show that x3 +y3+z3 =3xyz.​

Answer»

Answer:

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Step-by-step explanation:

Acc to identity -

X3 + y3 + c3 - 3XYZ = ( x+y+Z )(x2 + y2 + z2 - xy - yz - zx )

here x + y + z = 0

therefore, X3 + y 3 + z3 - 3 xyz = 0 * ( x2 + y2 + z2 - xy - yz - zx )

X3 + y3 + z3 - 3 xyz = 0

X3 + y3 + z3 = 3xyz



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