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If x+y+z =0, show that x3 +y3+z3 =3xyz. |
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Answer» Answer: hope it HELPS you Step-by-step explanation: Acc to identity - X3 + y3 + c3 - 3XYZ = ( x+y+Z )(x2 + y2 + z2 - xy - yz - zx ) here x + y + z = 0 therefore, X3 + y 3 + z3 - 3 xyz = 0 * ( x2 + y2 + z2 - xy - yz - zx ) X3 + y3 + z3 - 3 xyz = 0 X3 + y3 + z3 = 3xyz |
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