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If x+y+z=0 show that x³+y³+z³=2xyz using it find the value of (17)³-(5)³-(12)³ |
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Answer» Step-by-step explanation: Given x+y+z=0 solution- x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx) x³+y³+z³-3xyz=0(x²+y²+z²-xy-yz-zx) anything MULTIPLIED by 0 is 0 x³+y³+z³-3xyz=0 x³+y³+z³=3xyz hence proved
the VALUE of (17)³-(5)³-(12)³ let's CHECK if a+b+c=0 17+(-5)+(-12) 17-5-12 17-17 0 so,if a+b+c=0 then x³+y³+z³=3xyz =3*17*5*12 =3060 here is your answer HOPE it helps you please mark it as BRAINLIEST |
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