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If x+y=8 & xy=15 find the value of ( x^2+y^2) |
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Answer» x+y = 8 and XY = 15 Squaring (x+y) we (x+y)^2 = x^2 + y^2 + 2xy. ( since (a+b)^2 = a^2 + b^2+ 2ab) 8*8 = x^2 + y^2 + 2*15. ( since x+y = 8 and xy = 15) 64 = x^2 + y^2 + 30 64 - 30 = x^2 + y^2 x^2 + y^2 = 34 |
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