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If x+y=4, then find x³+y³+12xy-64 |
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Answer» x³ + y³ - 4³ + 3(4XY) (64 = 4³) (x + y - 4)(x² + y² + 4² - xy - 4Y - 4x) x + y = + 4 ( 4 + 4) * (x² + y² + 4² - xy - 4y - 4x) 0 * (x² + y² + 4² - xy - 4y - 4x) = 0 |
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