1.

If x+y=4, then find x³+y³+12xy-64

Answer»

x³ + y³ + 12XY - 64

x³ + y³ - 4³ + 3(4XY) (64 = 4³)

(x + y - 4)(x² + y² + 4² - xy - 4Y - 4x)

x + y = + 4

( 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)

0 * (x² + y² + 4² - xy - 4y - 4x)

= 0



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