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If x+y = 12 and xy=32 . find the value of x ^2+ y^2. plz solve its |
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Answer» GIVEN, x+y=12 xy=32 Now (x+y)² = x²+y²+2xy (12)²= x²+y²+2(32) 144= x²+y²+64 Therefore, x²+y²=144-64=80 |
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