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Answer» HEY BUDDY !!!!
HERE IS UR ANSWER!!!!
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Q:- ( x + y )^-1 × [ ( x )^-1 + ( y )^-1 ] =x^p × y^q
=》 1 ÷ ( x + y ) [ ( 1 ÷ x ) + ( 1 ÷ y ) ] =x^p × y^q
=》1 ÷ ( x + y ) [ ( x + y ) ÷ x y ] = x^p × y^q
=》1 ÷ x × y = x^p × y^q
=》( x × y )^-1 = x^p × y^q
=》 x^-1 × y^-1 = x^p × y^q
♤ On comparison
=》 p = -1 ; q = -1
♡ We have to prove { p + q + 2 = 0}
♤ PUTTING valu of p and q
=》 - 1 - 1 + 2
=》- 2 + 2
=》0
■ HENCE PROVED
HOPE HELPED
JAI HIND !!!
:-)
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