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If ∫(√x+x√x+x) dx=xaa+xbb+xcc+K such that x>0, then the value of 8abc is (where K is constant of integration and a,b and c are fixed constants)

Answer» If (x+xx+x) dx=xaa+xbb+xcc+K such that x>0, then the value of 8abc is (where K is constant of integration and a,b and c are fixed constants)


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