1.

If x +(x +1)+(x + 2) =18 , then x = ___________.

Answer»

Answer:

Value of x = 4

Step-by-step explanation:

GIVEN \:x^{2}+\frac{1}{x^{2}}=18

/* Subtract 2\times x \times \frac{1}{x} both SIDES of the equation, we get

x^{2}+\frac{1}{x^{2}}-2\times x \times \frac{1}{x}\\=18-2\times x \times \frac{1}{x}

\implies \left(x-\frac{1}{x}\RIGHT)^{2}=18-2

/* By algebraic identity:

a²+b²-2ab = (a-b)² */

\implies \left(x-\frac{1}{x}\right)^{2}=16

\implies \left(x-\frac{1}{x}\right)=±\sqrt{16}

x+\frac{1}{x} = ±4

Therefore,

Value of x = 4

Mark me as brainliest


Discussion

No Comment Found

Related InterviewSolutions