1.

If x=root 3+1/root 3-1 and y=root 3-1/root 3+1, then find the value of x2-xy+y2​

Answer»

Answer:

13

Step-by-step explanation:

x=(root 3+1)/(root3-1)

y=(root 3-1)/(root3+1)

SOLUTION :

x²-xy+y²

=(root 3+1)²/(root 3-1)² -(root 3-1)/(root 3+1)*(root 3+1)/(root 3-1)+(root 3-1)²/(root 3+1)²

="(3+1+2 root 3)²+(3+1-2 root 3)²"/(4-2 root 3)*(4+2 root 3)-1

=(4+3+4 root 3+4+3-4 root 3)/(2-root 3)*(2+root 3)-1

=(14/4-3)-1

=14-1

=13


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